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Humpty Dumpty Form solution in Clear category for Humpty Dumpty Form by Seaclaid
import math
def volume(h,w):
odp=(math.pi/6)*(h**2)*w
return odp
def surface(a,c,e):
return a
def checkio(h,w):
if h>w:
ee=(1-((w**2)/(h**2)))**.5
x=(h/(w*ee))*math.asin(abs(ee))
v=(math.pi*(w**2)*h)/6
print(v)
if h
Jan. 17, 2017
