First creative solution for How Much Gold by ciel - python coding challenges

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First solution in Creative category for How Much Gold by ciel

checkio=lambda dict: (sum(v if 'gold' in k else 1-v for k,v in dict.items())-1)/2

Feb. 23, 2014

Comments:

Sim0000 on March 13, 2014, 3:08 p.m.
short!!

ciel on March 14, 2014, 1:41 a.m.
Actually I used my pencil quite a lot. Perhaps the author thought this type of equation easily though. Anyway I solved this problem before Hubspot Amulet. Now that I have ported gauss() from my Ruby library, I should be able to apply it to this problem.

ciel on March 14, 2014, 5:22 a.m.
Used gauss(): <a href="http://www.checkio.org/mission/how-much-gold/publications/ciel/python-3/kinda_usual/">http://www.checkio.org/mission/how-much-gold/publications/ciel/python-3/kinda_usual/</a>

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