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First solution in Clear category for House Password by smirnoffs
import re
def checkio(data):
if len(data)<10:
print("Too short")
return False
patterns = ("\d+", "[a-z]", "[A-Z]")
for pattern in patterns:
if not re.search(pattern, data):
print("{} pattern failed".format(pattern))
return False
return True
#Some hints
#Just check all conditions
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio('A1213pokl') == False, "1st example"
assert checkio('bAse730onE4') == True, "2nd example"
assert checkio('asasasasasasasaas') == False, "3rd example"
assert checkio('QWERTYqwerty') == False, "4th example"
assert checkio('123456123456') == False, "5th example"
assert checkio('QwErTy911poqqqq') == True, "6th example"
Jan. 21, 2015
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