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6-liner: cleanest for full character range solution in Clear category for House Password by przemyslaw.daniel
def checkio(text):
is_any = lambda f: any(f(x) for x in text)
return is_any(str.isupper) and \
is_any(str.islower) and \
is_any(str.isdigit) and \
len(text) >= 10
Jan. 4, 2018
