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First solution in Clear category for House Password by locky.spb
import re
def checkio(data: str) -> bool:
#data ='asasasasasasasaas' #'bAse730onE4'
if len(data) < 10:
return False
# Just check if at least one symbol present for every group nedeed
if all([re.search('[0-9]', data), \
re.search('[a-z]', data), \
re.search('[A-Z]', data)]):
return True
else:
return False
Sept. 8, 2019
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