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First solution in Clear category for House Password by jtarnowska
def checkio(data):
digits = "0123456789"
upp = "ABCDEFGHIJKLMNOPRSTUVWQXYZ"
low = "abcdefghijklmnoprsruvwqxyz"
count_length = 0
count_digit = 0
count_upp = 0
count_low = 0
if len(data) >= 10:
count_length += 1
for i in range (len(data)):
if data[i] in digits:
count_digit += 1
for i in range (len(data)):
if data[i] in upp:
count_upp += 1
for i in range (len(data)):
if data[i] in low:
count_low += 1
if count_length != 0 and count_digit != 0 and count_upp != 0 and count_low != 0:
return True
else:
return False
#Some hints
#Just check all conditions
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio('A1213pokl') == False, "1st example"
assert checkio('bAse730onE4') == True, "2nd example"
assert checkio('asasasasasasasaas') == False, "3rd example"
assert checkio('QWERTYqwerty') == False, "4th example"
assert checkio('123456123456') == False, "5th example"
assert checkio('QwErTy911poqqqq') == True, "6th example"
Jan. 16, 2017
