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all & any solution in Clear category for House Password by cyprianos
def checkio(data):
return all([
len(data) >= 10,
any([x.isdigit() for x in data]),
any([x.islower() for x in data]),
any([x.isupper() for x in data])
])
#Some hints
#Just check all conditions
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio('A1213pokl') == False, "1st example"
assert checkio('bAse730onE4') == True, "2nd example"
assert checkio('asasasasasasasaas') == False, "3rd example"
assert checkio('QWERTYqwerty') == False, "4th example"
assert checkio('123456123456') == False, "5th example"
assert checkio('QwErTy911poqqqq') == True, "6th example"
Oct. 26, 2015
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