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First solution in Clear category for House Password by ccortello
def checkio(data):
#a password needs to pass the following:
#the password is long enough
if len(data) < 10:
return False
#the password contains mixture of upper and lower characters
elif data == data.lower():
return False
elif data == data.upper():
return False
#the password contains a digit
elif not any(i.isdigit() for i in data):
return False
#if all of the previous checks passed, then the password is valid
return True
#Some hints
#Just check all conditions
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio('A1213pokl') == False, "1st example"
assert checkio('bAse730onE4') == True, "2nd example"
assert checkio('asasasasasasasaas') == False, "3rd example"
assert checkio('QWERTYqwerty') == False, "4th example"
assert checkio('123456123456') == False, "5th example"
assert checkio('QwErTy911poqqqq') == True, "6th example"
May 19, 2015