First uncategorized solution for House Password by Polaroid - python coding challenges

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First solution in Uncategorized category for House Password by Polaroid

def checkio(data):
    'Return True if password strong and False if not'
    if len(data) < 10 or data == data.lower() or data == data.upper() or sum(i.isdigit() for i in data) == 0 :
        return False
    return True

if __name__ == '__main__':
    assert checkio('A1213pokl')==False, 'First'
    assert checkio('bAse730onE4')==True, 'Second'
    assert checkio('asasasasasasasaas')==False, 'Third'
    assert checkio('QWERTYqwerty')==False, 'Fourth'
    assert checkio('123456123456')==False, 'Fifth'
    assert checkio('QwErTy911poqqqq')==True, 'Sixth'
    print('All ok')

Nov. 9, 2012

Comments:

delta14 on Nov. 17, 2012, 8:45 p.m.
assert checkio('aaaaaaaaaaA0')==True Doesn't work with this one

Polaroid on Nov. 18, 2012, 2:03 a.m.
yes it works. You know that '0'.isdigit()==1, right ?

delta14 on Nov. 18, 2012, 9:57 a.m.
My bad, I misread your code.

Polaroid on Nov. 18, 2012, 2:03 a.m.
yes it works. You know that '0'.isdigit()==1, right ?

jey on Nov. 23, 2012, 11:56 a.m.
The fastest solution

etuardu on Dec. 6, 2012, 11:33 p.m.
This code is so clever but... it fall into a naive pleonasm with "if (condition) then false else true". One can just return the (negated) condition!

Polaroid on May 22, 2013, 8:16 p.m.
yes, in fact i wrote it very quickly just to try the first thing that came to my mind (sort of draft) and the problem is that... it worked and we cannot remove our solutions.

Vachenzo on May 22, 2013, 8:23 p.m.
You could always try writing a new solution and publishing that.

Polaroid on May 22, 2013, 8:37 p.m.
You're right, i did it, thanks. Check my 'One line' solution.

AndriusMk on Dec. 11, 2012, 3:50 p.m.
This is really great and simple solution!

infinitylX on March 7, 2013, 1:24 p.m.
<pre class='brush: python'> return True </pre> Interesting and awesome solution.

abu on May 22, 2013, 7:25 p.m.
Please, explain this solution in details. I used python visualizer, but i dont understand how we iterate the string.

Polaroid on May 22, 2013, 8:26 p.m.
i.isdigit() for i in data => creates a list of True and False depending if each caracter is a digit (for exemple 'Bob54' gives [False, False, False, True, True]). Then sum() will calculate the sum of all items of the list, and python sees True as 1 and False as 0, so if sum()==0 there is no digit in the string.

abu on May 22, 2013, 8:59 p.m.
thx)

Maxima on July 10, 2013, 7:59 p.m.
Edit: sorry, duplicate for etuardu message.

Strings Theory

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