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First solution in Creative category for House Password by Michal_Adamski98
def checkio(data):
d=len(data)
if(d>=10):
warunek1=1
else:
return False
warunek2=0
warunek3=0
warunek4=0
for i in range(d):
if(data[i].isupper()==True):
warunek2+=1
if(data[i].islower()==True):
warunek3+=1
if(data[i].isnumeric()==True):
warunek4+=1
if(warunek1==1 and warunek2>=1 and warunek3>=1 and warunek4>=1):
return True
else:
return False
#Some hints
#Just check all conditions
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio('A1213pokl') == False, "1st example"
assert checkio('bAse730onE4') == True, "2nd example"
assert checkio('asasasasasasasaas') == False, "3rd example"
assert checkio('QWERTYqwerty') == False, "4th example"
assert checkio('123456123456') == False, "5th example"
assert checkio('QwErTy911poqqqq') == True, "6th example"
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
Oct. 19, 2017
