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First solution in Clear category for House Password by LCY-Chegy
def checkio(data):
security = True
upc = 0
lpc = 0
dc = 0
for i,val in enumerate(data):
if val.isdigit():
dc+=1
elif val.isupper():
upc+=1
elif val.islower():
lpc+=1
if dc > 0 and upc > 0 and lpc > 0:
security = True
else:
security = False
if len(data) < 10:
security = False
#replace this for solution
return security
#Some hints
#Just check all conditions
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio('A1213pokl') == False, "1st example"
assert checkio('bAse730onE4') == True, "2nd example"
assert checkio('asasasasasasasaas') == False, "3rd example"
assert checkio('QWERTYqwerty') == False, "4th example"
assert checkio('123456123456') == False, "5th example"
assert checkio('QwErTy911poqqqq') == True, "6th example"
Oct. 1, 2015
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