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First solution in Clear category for The Hamming Distance by Chramar
def checkio(n, m):
a = "{0:{fill}20b}".format(n, fill='0')
b = "{0:{fill}20b}".format(m, fill='0')
cnt=0
print(a)
print(b)
for i in range(len(a)):
if a[i]!=b[i]:
cnt+=1
return cnt
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(117, 17) == 3, "First example"
assert checkio(1, 2) == 2, "Second example"
assert checkio(16, 15) == 5, "Third example"
Oct. 14, 2016
