1-liner itertools groupby clear solution for Group Equal consecutive by swagg010164 - python coding challenges

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1-liner itertools groupby solution in Clear category for Group Equal consecutive by swagg010164

from itertools import groupby

def group_equal(a):
    return [list(group) for key, group in groupby(a)]

Dec. 8, 2019

Comments:

Kirill_Morhun-Pospolitaki on Jan. 29, 2020, 7:05 p.m.
<p>Short and clear. Thanks!</p>

vlad.bezden on Feb. 13, 2020, 1:44 p.m.
<p>Great solution using itertools.groupby +4. In Python there is a convention to use "_" for variables that are not going to be used. So instead of "key" I would use "_".</p>

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