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Itertools solution in Creative category for Group Equal consecutive by TrangOul
import itertools
def group_equal(els):
return [[i] * len(list(j)) for i, j in itertools.groupby(els)]
if __name__ == '__main__':
print("Example:")
print(group_equal([1, 1, 4, 4, 4, "hello", "hello", 4]))
# These "asserts" are used for self-checking and not for an auto-testing
assert group_equal([1, 1, 4, 4, 4, "hello", "hello", 4]) == [[1,1],[4,4,4],["hello","hello"],[4]]
assert group_equal([1, 2, 3, 4]) == [[1], [2], [3], [4]]
assert group_equal([1]) == [[1]]
assert group_equal([]) == []
print("Coding complete? Click 'Check' to earn cool rewards!")
June 30, 2022
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