No import clear solution for Group Equal consecutive by OrginalS - python coding challenges

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No import solution in Clear category for Group Equal consecutive by OrginalS

def group_equal(els):
    res = []
    try:
        tmp = [els[0]]
    except IndexError:
        return []
    for elm in els[1:]+[None]:
        if elm == tmp[0]:
           tmp.append(elm)
        else:
            res.append(tmp)
            tmp = [elm]
    return res

Oct. 6, 2019

Comments:

bravebug on April 19, 2020, 2:54 p.m.
Clear and readable! Thanks!

Mysta on Feb. 21, 2022, 7:44 a.m.
I learned the rule of thumb, that using exceptions to control the program flow is not really good coding style. In this case it would be sufficient to write <pre class='brush: python'>if not els: return [] </pre> But what I really like: The idea to add [None] to the remaining els list to ensure that the last list is also added to the result list is great!

Master of the Time Stone

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