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First solution in Clear category for Group Equal consecutive by Molot
def group_equal(els):
res = []
for n, elem in enumerate(els):
if n == 0:
res.append([elem])
else:
if elem == res[-1][-1]:
res[-1].append(elem)
else:
res.append([elem])
return res
if __name__ == '__main__':
print("Example:")
print(group_equal([1, 1, 4, 4, 4, "hello", "hello", 4]))
# These "asserts" are used for self-checking and not for an auto-testing
assert group_equal([1, 1, 4, 4, 4, "hello", "hello", 4]) == [[1,1],[4,4,4],["hello","hello"],[4]]
assert group_equal([1, 2, 3, 4]) == [[1], [2], [3], [4]]
assert group_equal([1]) == [[1]]
assert group_equal([]) == []
print("Coding complete? Click 'Check' to earn cool rewards!")
Jan. 26, 2019
