First clear solution for Group Equal consecutive by Moff - python coding challenges

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First solution in Clear category for Group Equal consecutive by Moff

def group_equal(els):
    result = []
    pred = None
    for el in els:
        if el == pred:
            result[-1].append(el)
        else:
            result.append([el])
        pred = el
    return result

Dec. 6, 2018

Comments:

rodka81 on May 28, 2019, 9:23 a.m.
<p>Clear solution without using itertools</p>

scottdg on June 12, 2019, 12:18 a.m.
<p>Very clean. Thanks for NOT using an import! :)</p>

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