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First solution in Clear category for Golden Pyramid by tarasenkoa
def count_gold(pyramid):
l = [0] * len(pyramid)
for row in pyramid:
cl = list(l)
for i,v in enumerate(row):
if i == 0 or not cl[i-1] + v > cl[i] + v:
l[i] = v + cl[i]
else:
l[i] = v + cl[i-1]
return max(l)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert count_gold((
(1,),
(2, 3),
(3, 3, 1),
(3, 1, 5, 4),
(3, 1, 3, 1, 3),
(2, 2, 2, 2, 2, 2),
(5, 6, 4, 5, 6, 4, 3)
)) == 23, "First example"
assert count_gold((
(1,),
(2, 1),
(1, 2, 1),
(1, 2, 1, 1),
(1, 2, 1, 1, 1),
(1, 2, 1, 1, 1, 1),
(1, 2, 1, 1, 1, 1, 9)
)) == 15, "Second example"
assert count_gold((
(9,),
(2, 2),
(3, 3, 3),
(4, 4, 4, 4)
)) == 18, "Third example"
Feb. 25, 2015
