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Squaring the Circle solution in Clear category for Geometry Figures by flpo
from math import pi
def rounded(f): return lambda x: round(f(x), 2)
class Parameters:
def __init__(self, par):
self.par = par
def choose_figure(self, figure):
self.figure = figure
@rounded
def area(self):
return self.figure.area(self.par)
@rounded
def perimeter(self):
return self.figure.perimeter(self.par)
@rounded
def volume(self):
return self.figure.volume(self.par)
class RegularPoly:
def perimeter(self, par):
return self.nsides * par
def area(self, par):
return par ** 2 * self.phi
volume = lambda *_: 0
class Circle(RegularPoly): nsides, phi = pi * 2, pi
class Triangle(RegularPoly): nsides, phi = 3, 0.43301
class Square(RegularPoly): nsides, phi = 4, 1
class Pentagon(RegularPoly): nsides, phi = 5, 1.72048
class Hexagon(RegularPoly): nsides, phi = 6, 2.598076211
class Cube(RegularPoly): nsides, phi, volume = 12, 6, 3..__rpow__
June 23, 2018
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