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Simple solution in Clear category for Friends by BoguslawKalka
__author__ = 'boogi'
class Friends:
def __init__(self, connections=[]):
self.connections = set([])
for conn in connections:
self.connections.add(frozenset(conn))
def add(self, connection):
if connection in self.connections:
return False
else:
self.connections.add(frozenset(connection))
return True
def remove(self, connection):
try:
self.connections.remove(connection)
return True
except KeyError:
return False
def names(self):
ret = set([])
for conn in self.connections:
ret.update(conn)
return ret
def connected(self, name):
ret = set([])
for conn in self.connections:
if name in conn:
ret.update(conn)
try:
ret.remove(name)
except KeyError:
pass
return ret
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
letter_friends = Friends(({"a", "b"}, {"b", "c"}, {"c", "a"}, {"a", "c"}))
digit_friends = Friends([{"1", "2"}, {"3", "1"}])
assert letter_friends.add({"c", "d"}) is True, "Add"
assert letter_friends.add({"c", "d"}) is False, "Add again"
assert letter_friends.remove({"c", "d"}) is True, "Remove"
assert digit_friends.remove({"c", "d"}) is False, "Remove non exists"
assert letter_friends.names() == {"a", "b", "c"}, "Names"
assert letter_friends.connected("d") == set(), "Non connected name"
assert letter_friends.connected("a") == {"b", "c"}, "Connected name"
Dec. 8, 2014
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