First clear solution for Friendly Number by saklar13 - python coding challenges

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First solution in Clear category for Friendly Number by saklar13

def friendly_number(number, base=1000, decimals=0, suffix='',
                    powers=['', 'k', 'M', 'G', 'T', 'P', 'E', 'Z', 'Y']):
    x = 0
    while abs(number) >= base ** (x+1) and x + 1 < len(powers): x += 1
    number /= base ** x
    number = round(number, decimals) if decimals else int(number)
    return '{number:.{decimals}f}{0}{suffix}'.format(powers[x], **locals())

Jan. 27, 2015

Strings Theory

0 %

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