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One long line solution in Creative category for Friendly Number by lightholy
def friendly_number(number, base=1000, decimals=0, suffix='',
powers=['', 'k', 'M', 'G', 'T', 'P', 'E', 'Z', 'Y']):
"""
Format a number as friendly text, using common suffixes.
"""
return '-' + friendly_number(-number, base, decimals, suffix, powers) if number < 0 else friendly_number(number / float(base), base, decimals, suffix, powers[1:]) if number >= base and len(powers) > 1 else ('%%.%df' % decimals if decimals else '%d') % number + powers[0] + suffix
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert friendly_number(102) == '102', '102'
assert friendly_number(10240) == '10k', '10k'
assert friendly_number(12341234, decimals=1) == '12.3M', '12.3M'
assert friendly_number(12461, decimals=1) == '12.5k', '12.5k'
assert friendly_number(1024000000, base=1024, suffix='iB') == '976MiB', '976MiB'
March 28, 2014
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