Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Friendly Number by kv.polyanskiy
def friendly_number(number, base=1000, decimals=0, suffix='',
powers=['', 'k', 'M', 'G', 'T', 'P', 'E', 'Z', 'Y']):
"""
Format a number as friendly text, using common suffixes.
"""
result = number
index_power = 0
for i in range(len(powers)-1):
if abs(result) < base:
break
result, index_power = number / (base ** (i + 1)), i + 1
result = int(result) if decimals == 0 else round(result, decimals)
return "{0:0.{1}f}".format(round(result, decimals), decimals) + powers[index_power] + suffix
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert friendly_number(102) == '102', '102'
assert friendly_number(10240) == '10k', '10k'
assert friendly_number(12341234, decimals=1) == '12.3M', '12.3M'
assert friendly_number(12461, decimals=1) == '12.5k', '12.5k'
assert friendly_number(1024000000, base=1024, suffix='iB') == '976MiB', '976MiB'
assert friendly_number(-150, base=100, powers=["","d","D"]) == "-1d"
assert friendly_number(255000000000, powers=["","k","M"]) == '255000M'
assert friendly_number(10**24) == '1Y'
May 29, 2015
