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First solution in Clear category for Friendly Number by TheOne
def friendly_number(number, base=1000, decimals=0, suffix='',
powers=['', 'k', 'M', 'G', 'T', 'P', 'E', 'Z', 'Y']):
"""
Format a number as friendly text, using common suffixes.
"""
i = 0
while abs(number) >= base and i < len(powers) - 1:
if number % base:
number /= base
else:
number //= base
i += 1
if decimals:
str_number = (str(round(number, decimals)) + ('.' if isinstance(number, int) else '')).\
ljust(decimals + 1 + len(str(int(number))), '0')
else:
str_number = str(int(number))
return str_number + powers[i] + suffix
# These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert friendly_number(102) == '102', '102'
assert friendly_number(10240) == '10k', '10k'
assert friendly_number(12341234, decimals=1) == '12.3M', '12.3M'
assert friendly_number(12461, decimals=1) == '12.5k', '12.5k'
assert friendly_number(1024000000, base=1024, suffix='iB') == '976MiB', '976MiB'
Nov. 5, 2015
