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First solution in Clear category for Friendly Number by PawelMartyniuk
def friendly_number(number, base=1000, decimals=0, suffix='',
powers=['', 'k', 'M', 'G', 'T', 'P', 'E', 'Z', 'Y']):
"""
Format a number as friendly text, using common suffixes.
"""
main = float(number)
powerLength = len(powers)
i = 0
while abs(main) >= base and i < powerLength - 1:
main /= base
i += 1
if decimals == 0:
main = int(main)
else:
main = round(main, decimals)
fmt = "%."+str(decimals)+"f"+powers[i]+suffix
ret = fmt % main
return ret
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert friendly_number(102) == '102', '102'
assert friendly_number(10240) == '10k', '10k'
assert friendly_number(12341234, decimals=1) == '12.3M', '12.3M'
assert friendly_number(12461, decimals=1) == '12.5k', '12.5k'
assert friendly_number(1024000000, base=1024, suffix='iB') == '976MiB', '976MiB'
Oct. 31, 2016
