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First solution in Clear category for Friendly Number by Coamo
def friendly_number(number, base=1000, decimals=0, suffix='',
powers=['', 'k', 'M', 'G', 'T', 'P', 'E', 'Z', 'Y']):
glowna = float(number)
powerD = len(powers)
i = 0
while abs(glowna) >= base and i < powerD - 1:
glowna /= base
i += 1
if decimals == 0:
glowna = int(glowna)
else:
glowna = round(glowna, decimals)
return "{0:.{1}f}{2}{3}".format(glowna, decimals, powers[i], suffix)
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert friendly_number(102) == '102', '102'
assert friendly_number(10240) == '10k', '10k'
assert friendly_number(12341234, decimals=1) == '12.3M', '12.3M'
assert friendly_number(12461, decimals=1) == '12.5k', '12.5k'
assert friendly_number(1024000000, base=1024, suffix='iB') == '976MiB', '976MiB'
Nov. 24, 2016
