Short and clear clear solution for The Flat Dictionary by EdinsonUwU - python coding challenges

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Short and clear solution in Clear category for The Flat Dictionary by EdinsonUwU

def flatten(dictionary):
  def flattenAux(dictionary,key = None,nuevoDict = {},nameKey=""):
    try:
      for i in dictionary.keys():
        nameKey += i + '/'
        if (dictionary[i] == {}):
          nuevoDict[nameKey[:len(nameKey)-1]] = ""
        else:
          flattenAux(dictionary[i],i,nuevoDict,nameKey)
        nameKey = nameKey[:(len(nameKey)-len(i)-1)]
    except:
      nuevoDict[nameKey[:len(nameKey)-1]] = dictionary
    return nuevoDict
  return flattenAux(dictionary)

June 30, 2021

Look up in the Dict()

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