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divide once solution in Speedy category for Fizz Buzz by ys5883
TABLE = {
0: "Fizz Buzz",
3: "Fizz",
5: "Buzz",
6: "Fizz",
9: "Fizz",
10: "Buzz",
12: "Fizz",
}
def checkio(n):
try:
return TABLE[n % 15]
except KeyError:
return str(n)
#Some hints:
#Convert a number in the string with str(n)
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio(15) == "Fizz Buzz", "15 is divisible by 3 and 5"
assert checkio(6) == "Fizz", "6 is divisible by 3"
assert checkio(5) == "Buzz", "5 is divisible by 5"
assert checkio(7) == "7", "7 is not divisible by 3 or 5"
Aug. 16, 2014
