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First solution in Scary category for Fizz Buzz by spoty
# migrated from python 2.7
def checkio(number):
return (number % 15 == 0)*"Fizz Buzz" or (number % 3 == 0)*"Fizz" or (number % 5 == 0)*"Buzz" or repr(number)
Jan. 25, 2015
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