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Return solution in Clear category for Fizz Buzz by robert.bedner
def checkio(number: int) -> str:
if number % 15 == 0:
return 'Fizz Buzz'
if number % 5 == 0:
return 'Buzz'
if number % 3 == 0:
return 'Fizz'
return str(number)
Jan. 20, 2022
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