First clear solution for Fizz Buzz by panaro32 - python coding challenges

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First solution in Clear category for Fizz Buzz by panaro32

def checkio(n):
    return 'Fizz'*(not n%3)+' '*(not n%15)+'Buzz'*(not n%5) or str(n)

May 11, 2014

Comments:

infinitylX on July 7, 2014, 2:49 p.m.
Briliant!

panaro32 on July 8, 2014, 6:53 a.m.
Thanks! :)

ddouble on July 30, 2014, 5:44 a.m.
Less typing than me :) although i'm not a python coder (so i don't know all the code there) but i think i can manage :)

taras-sereda on Aug. 11, 2014, 7:37 a.m.
Smart solution:)

clockkent on Aug. 23, 2014, 5:41 a.m.
The part of adding a ' ' contingent on being divisible by 15 is brilliant. Bravo!

panaro32 on Aug. 24, 2014, 12:22 a.m.
Thank you!

Paul-Yuchao-Dong on Dec. 11, 2016, 7:59 a.m.
Totally agree on the `" "` part, I thought it couldn't be done!

MrJohanga on Sept. 17, 2014, 7:38 p.m.
It's creative but not easy readable solution.

Slausbang on Oct. 4, 2014, 3:48 p.m.
Definitely creative, but I'm not sure it's very clear.

mgreen on Oct. 19, 2014, 6:31 p.m.
great!

RonHelms on Oct. 19, 2014, 11:28 p.m.
clever! not sure it would be easy to debug, and it is not the clearest implementation. But it is definitely creative!

scrapple74 on Oct. 26, 2014, 4:09 p.m.
Like many have said, it's not very clear code, but it is clever and succint.

marshall.zheng on Nov. 5, 2014, 4:50 p.m.
quite smart!

SantaUA on Nov. 11, 2014, 7:41 p.m.
explaine, please )

jam on Nov. 14, 2014, 7:25 p.m.
Now I know - aliens with mental superpower exist!:)

Fedorovich on Nov. 20, 2014, 12:47 p.m.
But where if-else statements?

serhiideliiev on Nov. 20, 2014, 1:07 p.m.
It is an another way of solving, more smart and stylish.

koxt on Nov. 27, 2014, 9:27 p.m.
solution is too smart to be clear

sabareeshk on Dec. 11, 2014, 6:26 a.m.
good

marshall.zheng on Dec. 18, 2014, 6:02 a.m.
great!

mihassan on Dec. 25, 2014, 11:59 a.m.
Nice way to solve it, specially the way middle space is handled.

johnoommen on Dec. 29, 2014, 10:07 a.m.
That's definitely one way to do it.

theParasite on Jan. 7, 2015, 8:39 a.m.
oh god, thats really nice

TorA.D. on Jan. 10, 2015, 6:04 p.m.
very nice.

JjHack on Jan. 12, 2015, 2:44 a.m.
Very clever. Although I somewhat agree that it's not very readable, seeing solutions such as this as a Python n00b definitely helps see creative possibilities of solving even simple problems. It can only help.

numenor96_a1a2b7b06d624327a506 on Feb. 6, 2015, 11 a.m.
Amazing! I have published this solution in a more clear manner, if anybody still don't understand.

konrad.gadzina on Feb. 17, 2015, 1:22 p.m.
Great usage of python string*integer trick :) Although it's pretty hard to read

karel_chajim on Feb. 22, 2015, 3:29 p.m.
I was thinking about something one-sentenced and could not come up with anything. Good one!

CarlTurland42 on Feb. 25, 2015, 10:36 a.m.
Wow, very clever! Always impressed by the top answers

bcroswell on March 1, 2015, 8:50 p.m.
Simple is always better :)

jswhitworth on March 9, 2015, 6:05 a.m.
bravo. You obviously could have written the solution in more readable if/else logic if you wanted. I thought this was more entertaining. Cheers

AlexRad on March 13, 2015, 10:35 a.m.
Hard to understand

panaro32 on March 13, 2015, 3:04 p.m.
Type into your python command line: <pre class='brush: python'>"abc"*3 16%5 15%5 not 16%5 not 15%5 "abc"*True "abc"*False "abc" or "42" "" or "42" </pre> Then read my solution! Thank you for your input!

AlexRad on March 13, 2015, 7:34 p.m.
It use too many python tricks that can be changed in future. And it is not clear to understand.

gabo on May 5, 2015, 2:32 a.m.
Crystal-clear 'explanation', thnx

Raill on Feb. 5, 2016, 3:17 p.m.
I think would be hard to understand the code. But your examples make it simple. Tks.

vitorkusiaki on March 25, 2015, 12:38 p.m.
nice

lukasso on April 12, 2015, 7:41 p.m.
Cool :-)

panaro32 on April 18, 2015, 3:48 p.m.
Thanks! :-)

peter.j.fortuna on May 23, 2015, 7:36 p.m.
Woa... I have a long way to go in programming haha

toru on May 31, 2015, 7:57 p.m.
It's quite elegant! 1 == True, that's why we can multiply string by True.

Vedeshkin on June 1, 2015, 2:22 p.m.
Very cute!

programmerZ on June 16, 2015, 3:11 p.m.
Great solution to the problem, taught me something new about Python. Could someone go into more depth about how the or is handled here? Why is it not always printed? 'Fizz'(not n%3)+' '(not n%15)+'Buzz'*(not n%5) or str(n) I used my python compiler and noticed if we or a string with an empty string it will print out the other string. Does anyone know why this occurs?

panaro32 on June 18, 2015, 11:07 a.m.
'or' is a binary operator, that means it takes two arguments (A or B). If A is equivalent to True, that means bool(A) == True, then A or B == A. Otherwise (if A is equivalent to False, that means bool(A) == False), then A or B == B. We can think the code 'A or B' is equivalent to 'if A then A else B'. Here A == 'Fizz'(not n%3)+' '(not n%15)+'Buzz'*(not n%5) and B == str(n). So the output is A, a string contains 'Fizz', 'Buzz' or 'Fizz Buzz', unless bool(A) == False. Because A is a string, bool(A) == False if and only if A == '', the empty string (This case occurs only if n is not divisible by 3 and n is not divisible by 5). So if A == '' then the output is B.

Alexona on July 4, 2015, 10:12 a.m.
It is great to learn sth new about "or" :)

napoleon_blownaparte on July 30, 2015, 9:19 p.m.
Love it! I am brand new to Python so this totally blew my mind. Nice solution :)

Swaper on Aug. 8, 2015, 8:26 p.m.
WOW! simply briliant!

viktor.kryvyziuk on Aug. 14, 2015, 7:09 a.m.
Readability could be better. Strings concatenation is expensive operation.

jesusdarkjewel on Sept. 8, 2015, 11:51 a.m.
unreadable.

hotsolochi on Sept. 11, 2015, 9:01 a.m.
Briliant! You taught me something new, thank you!

jakow on Sept. 11, 2015, 9:50 p.m.
wow

abupoonjaby on Sept. 26, 2015, 3:50 a.m.
bomb - even a yr later

inna_salamonova on Oct. 1, 2015, 7:35 p.m.
Задрот

Jandec on Nov. 21, 2015, 11:34 a.m.
working and concise, but hard to grasp

ror on Nov. 24, 2015, 10:03 a.m.
good

vlad.kneu on Dec. 12, 2015, 6:39 a.m.
Cool)) Great idea.

omart on Dec. 21, 2015, 7:37 p.m.
Elegant short-circuiting solution :)

dhj on Jan. 14, 2016, 3:58 a.m.
Good solution, but not particularly clear for people learning how to program. Good for shortcuts and python idioms, but those are pretty advanced concepts and don't usually make for maintainable code.

kapilka06 on Jan. 31, 2016, 7:59 a.m.
Awesome!

CraxGrix on Feb. 27, 2016, 2:28 a.m.
Great!!

Cleviton on March 16, 2016, 1:16 p.m.
Very creative solution.

Aunmag on March 25, 2016, 9:25 a.m.
Very cool!

Vooja on April 2, 2016, 9:45 p.m.
Very nice work. Btw how long were you doing this code?

wuhuarui1992 on April 27, 2016, 4:56 a.m.
perfect.

Charen on May 22, 2016, 4:20 p.m.
This is awesome :)

forfriapple on June 22, 2016, 3:43 p.m.
nice

DavidFeher on July 3, 2016, 5:42 p.m.
i like that you managed to write a oneline code

msmyxz on Sept. 8, 2016, 10:44 a.m.
this is really cool! :)

transistor on Sept. 12, 2016, 3:53 p.m.
Creative one !

Ghost9495 on Sept. 27, 2016, 5:49 a.m.
very compact code :D

jstrzebonski on Sept. 28, 2016, 7:16 a.m.
This is great. I love the idea with string multiplication.

Jairo_Malanay on Oct. 21, 2016, 7:54 a.m.
Cool ! it requires me to reindent to understand :) ``` return 'Fizz'(not n%3)+ ' '(not n%15)+ 'Buzz'*(not n%5) <pre class='brush: python'> or str(n) </pre> ```

Sergey_Torik on Dec. 11, 2016, 10:57 p.m.
%15!!! ahhh that's the answer!!!

9Teen90Three on Feb. 7, 2017, 7:59 p.m.
Hello world! There is a man who absolutely fresh in programming at all (not also Python) (I am also fresh in English, so sorry if you don't understand something). In my comprehension if I want to check any conditions I have to use IF statement, but as we see here, it is not always necessary. So can anyone explain me how I can use this short method which include statements without IF? Maybe someone can give more examples? Exactly, I didn't understand how we can start using conditions, if we didn't use any statements? Is it some Python feature, or it is mutual? Thank you!

Lmaitre on Feb. 9, 2017, 10:38 a.m.
The best I've seen...Bravo

LOACH on Feb. 12, 2017, 2:52 a.m.
Another vote for it being a very intelligent solution but not clear.

rm0063vpedc15 on Feb. 27, 2017, 6:14 a.m.
Brilliant!!!!!

MylesK on March 27, 2017, 4:55 p.m.
Not very pythonic

epanchincevnikita3 on May 3, 2017, 3:34 p.m.
wow, so clean

Rocketich on Sept. 29, 2017, 9:51 a.m.
It means that we can mupltiply boolean with other types? Can you please give me link to documentation to this ?

Shantanu_Kamath on Nov. 19, 2017, 9:09 a.m.
Fantastic solution

advance138138 on Sept. 17, 2018, 3:58 a.m.
wow...

Berzhan_Kurmanov on Nov. 9, 2018, 3:38 p.m.
Oh my... this guy is a real genius!

jk928 on April 27, 2019, 9:25 p.m.
Very Elegant!!

anplaceb on July 19, 2019, 8:53 a.m.
Very original! But I don't understand something ^^" Why not 0 is True? And why not 1234 is False?

marianov1 on July 22, 2019, 9:59 p.m.
Beautiful.

glog79 on July 28, 2019, 3:33 p.m.
Wonderful!

Optimus47 on Dec. 10, 2019, 2:16 p.m.
I felt back to solutions page to find this. one-line is one-love!)

8weipan8 on March 27, 2020, 6:21 a.m.
"Simple" answer to simple question!

dusty5213 on April 7, 2020, 7:25 a.m.
It's playful, but as have been said above it's not good for maintaining. I believe The Zen of Python would be against to use this code, nevertheless, I like it just because I learned new stuff. As panaro32 mention: Copy and run this to better understand print("abc" * 3) print(16 % 5) print(15 % 5) print(not 16 % 5) print(not 15 % 5) print("abc" * True) print("abc" * False) print("abc" or "42") print("" or "42")

Steapn0806 on March 27, 2020, 12:27 p.m.
Wow

tkachuk.constantine on June 6, 2021, 3:11 p.m.
Thanks for reminding. I am waiting for the the time, when I recollect by myself. :))

CDG.Axel on Sept. 15, 2021, 7:24 p.m.
really great! two symbols shorter than my solution and really clear <pre class='brush: python'>return (str(n) if n % 5 else 'Buzz') if n % 3 else 'Fizz' if n % 5 else 'Fizz Buzz' </pre>

Strings and Integers

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