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Using itertools.compress solution in Creative category for Fizz Buzz by nilp0inter
#Your optional code here
#You can import some modules or create additional functions
from itertools import compress
def checkio(number):
fizz = not (number % 3)
buzz = not (number % 5)
return " ".join(compress(("Fizz", "Buzz"),
(fizz, buzz))) or str(number)
#Some hints:
#Convert a number in the string with str(n)
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio(15) == "Fizz Buzz", "15 is divisible by 3 and 5"
assert checkio(6) == "Fizz", "6 is divisible by 3"
assert checkio(5) == "Buzz", "5 is divisible by 5"
assert checkio(7) == "7", "7 is not divisible by 3 or 5"
Dec. 19, 2014
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