one liner creative solution for Fizz Buzz by makoto_yamagata - python coding challenges - Py.CheckiO

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one liner solution in Creative category for Fizz Buzz by makoto_yamagata

checkio = lambda n: ' '.join(x[1] for x in [(3,'Fizz'),(5,'Buzz')] if not n%x[0]) or str(n)

July 21, 2015

Strings and Integers

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