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fizzzzzzbzzzzzz solution in Scary category for Fizz Buzz by ma3ypok
def checkio(number):
fizz = "Fizz" if number % 3 == 0 else ""
buzz = "Buzz" if number % 5 == 0 else ""
return ("%s %s" % (fizz, buzz) if fizz or buzz else str(number)).strip()
April 11, 2015
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