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First solution in Clear category for Fizz Buzz by juliakhulla
def checkio(x):
if ((x % 5) ==0) and ((x % 3) == 0):
return 'Fizz Buzz'
elif (x % 5) == 0:
return 'Buzz'
elif (x % 3) == 0:
return 'Fizz'
else:
return str(x)
Nov. 23, 2016
