First clear solution for Fizz Buzz by darasg2008 - python coding challenges

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First solution in Clear category for Fizz Buzz by darasg2008

def checkio(number):
    if number%3==0:
        if number%5==0:
            return str("Fizz Buzz")
        else:
            return str("Fizz")
    elif number%5==0:
        return str("Buzz")
    else:
        return str(number)

Nov. 3, 2016

Strings and Integers

0 %

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