Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Fizz Buzz by artemiy330
def checkio(number):
if number % 3 == 0 and number % 5 == 0:
return ("Fizz Buzz")
elif number % 5 == 0:
return ("Buzz")
elif number % 3 == 0:
return ("Fizz")
else:
return str(number)
June 24, 2017
Comments:
