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First solution in Clear category for Fizz Buzz by arek.kowalski107
def checkio(x):
#x=input("give")
if x%3==0:
if x%5==0:
x="Fizz Buzz"
return x
else:
x="Fizz"
return x
else:
if x%5==0:
x="Buzz"
return x
else:
return str(x)
x=7
print(checkio(x))
Dec. 10, 2016
