First clear solution for Fizz Buzz by andriutwich - python coding challenges

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First solution in Clear category for Fizz Buzz by andriutwich

# migrated from python 2.7
def checkio(number):
    if number % 15 == 0:
        return "Fizz Buzz"
    if number % 5 == 0:
        return "Buzz"
    if number % 3 == 0:
        return "Fizz"
    return str(number)

print(checkio(15) == "Fizz Buzz")
print(checkio(6) == "Fizz")
print(checkio(5) == "Buzz")
print(checkio(7) == "7")

Jan. 13, 2017

Strings and Integers

0 %

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