Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Fizz Buzz by alwayswannafly
def checkio(number):
if number % 3 == 0 and number % 5 == 0:
return 'Fizz Buzz'
elif number % 3 == 0:
return 'Fizz'
elif number % 5 == 0:
return 'Buzz'
else:
return str(number)
Nov. 16, 2016
