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Second solution in Uncategorized category for Fizz Buzz by UFO665
def checkio(number):
if number % 3 == 0 and number % 5 == 0:
return "Fizz Buzz"
elif number % 3 == 0:
return "Fizz"
elif number % 5 == 0:
return "Buzz"
return str(number)
Dec. 1, 2015
