Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Fizz Buzz by Rudeboyz_Squad
def checkio(n: int) -> str:
if n % 3 == 0:
return "Fizz Buzz" if n % 5 == 0 else "Fizz"
if n % 5 == 0:
return "Buzz"
return f"{n}"
March 6, 2019
Comments:
