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First solution in Speedy category for Fizz Buzz by MaximLialin
def checkio(number):
if number%3 == 0 and number%5 == 0:
return "Fizz Buzz"
elif number%3 == 0:
return "Fizz"
elif number%5 == 0:
return "Buzz"
return str(number)
if __name__ == '__main__':
assert checkio(15) == "Fizz Buzz", "15 is divisible by 3 and 5"
assert checkio(6) == "Fizz", "6 is divisible by 3"
assert checkio(5) == "Buzz", "5 is divisible by 5"
assert checkio(7) == "7", "7 is not divisible by 3 or 5"
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
May 2, 2018