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Scalable solution in Clear category for Fizz Buzz by ChrisBlue
# Your optional code here
# You can import some modules or create additional functions
def checkio(number: int) -> str:
# Your code here
# It's main function. Don't remove this function
# It's using for auto-testing and must return a result for check.
# replace this for solution
Words = [[3,"Fizz"],[5,"Buzz"]]
Solution = []
for x in Words:
if number%x[0]==0:
Solution.append(x[1])
return str(number) if len(Solution)==0 else " ".join(Solution)
# Some hints:
# Convert a number in the string with str(n)
# These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
print('Example:')
print(checkio(15))
assert checkio(15) == "Fizz Buzz", "15 is divisible by 3 and 5"
assert checkio(6) == "Fizz", "6 is divisible by 3"
assert checkio(5) == "Buzz", "5 is divisible by 5"
assert checkio(7) == "7", "7 is not divisible by 3 or 5"
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
Feb. 27, 2020
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