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Simple and Clean solution in Clear category for Fizz Buzz by Brian_Sin
def checkio(x):
if x % 3 == 0 and x % 5 == 0:
return "Fizz Buzz"
if x % 3 == 0:
return "Fizz"
if x % 5 == 0:
return "Buzz"
else:
return str(x)
March 11, 2020
