First clear solution for First Word by ndj_ys - python coding challenges

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First solution in Clear category for First Word by ndj_ys

def first_word(text: str) -> str:
    reText = text.translate(str.maketrans({",":" ",".":" "}))
    textList = reText.split(" ")
    for word in range(len(textList)):
        if textList[word] != "":
            return textList[word]

Aug. 9, 2018

Comments:

Tinus_Trotyl on Aug. 26, 2018, 12:08 p.m.
Nice solution !

ndj_ys on Aug. 26, 2018, 12:09 p.m.
Thanks!

Tinus_Trotyl on Aug. 26, 2018, 12:59 p.m.
Yeah, I like things done simply, without leaning only any libraries . By the way, I've done some streamlining on yours :-) <pre class='brush: python'>def first_word(text: str) -> str: for word in text.translate(str.maketrans({",":" ",".":" "})).split(" "): if word: return word </pre>

ndj_ys on Aug. 26, 2018, 2:37 p.m.
That was really helpful! Thanks a lot! <pre class='brush: python'>The following sentences ... >>if word: >> return word You mean word is "" --> False word length are one or more --> True ? </pre>

Tinus_Trotyl on Aug. 27, 2018, 7:38 p.m.
Yes, right, And more: empty list, tuple, set are all False. (But `[[]]` eg. again is True, since it's not empty as it contains an empty list). Also any number except 0 is True.

ndj_ys on Aug. 27, 2018, 9:46 p.m.
Thank you for teaching me lots of things!!

Tinus_Trotyl on Aug. 28, 2018, 8:26 a.m.
Your're welcome. If you want to learn on python I think this might be a good read . (I learned few useful things from here and still do). <a href="https://automatetheboringstuff.com/chapter0/">Automate the boring stuff</a> Have fun :)

Strings and Integers

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