First clear solution for First Word by Moff - python coding challenges

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First solution in Clear category for First Word by Moff

import re


def first_word(text: str) -> str:
    return re.search("([\w']+)", text).group(1)

Nov. 16, 2017

Comments:

damayi on Dec. 6, 2017, 8:17 a.m.
this is amazing!

danycode on Jan. 1, 2018, 9:18 p.m.
wow I made some for loops and isalpha() I think I still have a long way to go... but I keep on going.

PatinaHo on Aug. 3, 2018, 5:05 a.m.
I did the same!

Sophie_Pan on May 29, 2020, 12:24 a.m.
I did the same!! hahaha

HandsomeKevin on Jan. 25, 2018, 6:59 a.m.
I made some for loops and isalpha() and split to solve this...Still a long way to go

georimer on Feb. 5, 2018, 1:07 p.m.
You are cheater :D

BeautifulFlowers on Feb. 10, 2018, 2:50 a.m.
so cool!

hjoulal_84530a72901c4ba4a2ed6a on Feb. 15, 2018, 1:10 a.m.
lol I had to alter the text to get to the first word. thank you for this solution :)

yerik on Feb. 27, 2018, 10:04 a.m.
what???my god！！！！import re......amazing!!!!!!!!!!!!!!!!!!!!!!!!

deskomor on Feb. 27, 2018, 2:02 p.m.
i did re but with +5 more lines,but im just starting.

Bucu88 on March 7, 2018, 3:30 p.m.
What about word "don't" ?

WillemLee on May 9, 2018, 3:06 a.m.
If you have Numbers？

heios on May 9, 2018, 2:47 p.m.
i cant manage to understand what this code mean, especially the ([\w']+) , the documentation says it is a pattern? but what pattern.. can somebody explain?

Moff on May 19, 2018, 9 p.m.
`()` - means group `[]` - set of symbols `\w` - any letter `[\w']` - any letter or `'` `[\w']+` - any letter or `'` one or more times profit

dusty5213 on April 6, 2020, 4:26 a.m.
Does somebody know where I can get a good simple explanation with examples of the whole re module? Because for working with strings it's awesome and to be honest I don't quite the explanation on python.org. The whole re module seems to me so complex,vast and the syntax so complicated.

arvie on May 11, 2020, 7:10 a.m.
I don't know any introductions, but this might be a good start: <a href="https://regexone.com">https://regexone.com</a> As regular expressions are common in every programming language, you don't need to focus on Python. Except for some minor details the syntax is the same. This "Sandbox" helped me a lot, because it shows the resolved parts in real time: <a href="https://regex101.com">https://regex101.com</a>

ichandanpratap on Dec. 23, 2020, 4:33 p.m.
Great ! I need to practice regex now.

leggewie on May 23, 2021, 11:39 a.m.
I can recommend <a href="https://www.w3schools.com/python/python_regex.asp">https://www.w3schools.com/python/python_regex.asp</a> and <a href="https://regex101.com">https://regex101.com</a>

Gabegonzo128 on Jan. 27, 2022, 6:26 a.m.
<a href="http://youtube.be/K8L6KVGG-7o">http://youtube.be/K8L6KVGG-7o</a> I found this and it came in very helpful for me personally. Just incase the link doesn't work the content creators name is Corey Schafer.

madi.muratuly on May 22, 2018, 5:37 a.m.
GJ )

yuyin110 on June 4, 2018, 8:14 a.m.
If the string start with number (example:"1. put your hands up "),the script get a wrong reply

murlakatamenka on Sept. 17, 2018, 7:54 p.m.
This example doesn't satisfy <blockquote> Precondition: the text can contain a-z A-Z , . ' </blockquote> You could use `[a-zA-Z']+` as regex if numbers were allowed.

jcs42 on Sept. 27, 2018, 10:39 a.m.
why would this allow numbers? does this not mean only uppercase and lower can letters?

murlakatamenka on Sept. 27, 2018, 8:07 p.m.
I see my reply isn't clear enough if read without context (<a href="https://py.checkio.org/mission/first-word/publications/Moff/python-3/first/share/93620c5645c93d63a4e0128f170f00f7/#comment-64496">message</a> by @yuyin110). What I meant is: 1. if numbers were allowed in the input sequence (like "1. put your hands up " @yuyin110 provides as an example) 2. then regex `[\w']+` of this solution won't work for detecting words since `\w` = letters + numbers, and numbers aren't part of words 3. so we need to use a more strict regex which is for letters and `'` only = `[a-zA-Z']+` Hope it's clear now.

domgregori on Nov. 13, 2018, 4:21 p.m.
Also, \w includes the underscore '_' character. That wasn't one of the parameters in the info but definitely something to keep in mind. [a-z']+ with re.I flag is how I did it.

mathieu.roesch on July 18, 2018, 4:30 p.m.
import re changed my life <3

bluescao on July 25, 2018, 6:11 a.m.
beautiful

lunskra on Aug. 16, 2018, 7:38 a.m.
return re.search("[\w']+",text)[0] works as well. What is the group(1) needed for? (I basically reconstructed your solution from memory and forgot the group and it still worked. Am I missing something?)

V.Shkaberda on Oct. 29, 2018, 7:53 p.m.
This syntax is new since version `3.6`. As you can read in <a href="https://docs.python.org/3/library/re.html#re.Match.__getitem__">Docs</a>: <blockquote> This is identical to `m.group(g)`. This allows easier access to an individual group from a match. </blockquote>

k.muresource on Sept. 16, 2018, 6:51 a.m.
great!

st232bd on Oct. 22, 2018, 4:29 p.m.
I reinvented the wheel. It was usefull.

mdudhnale on Jan. 15, 2019, 6:43 p.m.
I can't understand what this regex means. Some explanations will be appreciated.

Dariaki on Jan. 20, 2019, 10:23 p.m.
It becomes easy when you familiarize yourself with the basic rules of RE. \w -- any letter/digit/underbar [ ] -- a set of characters, e.g. [\w'] means either any letter/digit/underbar or apostrophe ' + -- says the character should appear 1 or more times ()-- a group Thus, re.search("([\w']+)", text).group(1) means find either letter/digit/underbar or apostrophe which should appear 1 or more times in our text and all that we put within a group, so then we just use a group function to return it. I believe there is no need in specifying the number of the group (since we have only one), so group() suits as well, but anyway:)

Greynar on Feb. 28, 2020, 9:38 a.m.
This is really good explanation! Thank you!

jirikovo on Feb. 26, 2019, 10:12 a.m.
Haha, love theese one-line hacks!

armo.cm.sa on Dec. 10, 2019, 4:53 a.m.
this was awesome man, i made some loops as well + isalpha(), works well but hell of lines :)) I've learned something new here, thanks for sharing with us.

WreakHavoc on Jan. 7, 2020, 5:24 p.m.
There's just one problem. What happens if the input is just one single quote and nothing else? The REGEX will return it as a word, even though it isn't. I'd use the REGEX \w+['\w]*

Davide_Luise on Feb. 27, 2020, 5:12 p.m.
what's the need of using group??

krzysztofrrr on May 3, 2020, 10:18 p.m.
almost the same, but didn't know it's enough to put \w' insdide []

eclipse7723 on July 28, 2020, 10:25 p.m.
I think it's not great idea to use regex in Elementary tasks...

Jonethan on Sept. 30, 2020, 12:12 p.m.
In comparsion with my code (19 lines), you're code is holy f*cking genius

krzychu_gr on Oct. 4, 2020, 9:41 p.m.
when the string is empty or contains only non [\w'] characters, this raises error...

Striga on Nov. 8, 2020, 5:14 p.m.
fancy!

Rush_iam on Nov. 13, 2020, 8:05 p.m.
Very nice and educational for many use of Regular Expression. Thanks!

Safwan_Samsudeen on Nov. 24, 2020, 11 a.m.
I used `re.split(r'\W(\w[^,. !?"])', text)[1]`. What's the difference?

drill3r92 on Dec. 3, 2020, 10:48 a.m.
Wow! Good thinking! With regular expression, this case looking clear and fast

drill3r92 on Dec. 3, 2020, 10:52 a.m.
Wow! Good thinking! With regular expression, this case looking clear and fast.

FUbaer on Dec. 12, 2020, 7:55 p.m.
some comments will be helpful

drill3r92 on Dec. 17, 2020, 5:19 p.m.
Wow! Good thinking! With regular expression, this case looking clear and fast.

drill3r92 on Dec. 31, 2020, 12:17 p.m.
Wow! Good thinking! With regular expression, this case looking clear and fast.

sytchov1 on Jan. 2, 2021, 9:33 a.m.
Nice smart solution

sytchov1 on Jan. 2, 2021, 9:48 a.m.
Nice short solution! But I'm really don't understand why we need choose 1 element from group instead 0 SadCat

new_hoschi on Feb. 15, 2021, 3:10 p.m.
You categorized this as clear, so I would appreciate a short description. Imagine someone solving this task differently and not being used to regex. Then its hard to learn anything from your solution.

SolarLee-83 on March 2, 2021, 4:53 a.m.
Thanks, that is really cool!

kekeMemo0001 on March 5, 2021, 8:13 a.m.
Fantastic! I tried so many times. but give me an error. learn from the solution.

Juntian_Deng on March 11, 2021, 9:24 p.m.
This is a really clear and good solution!

Juntian_Deng on March 16, 2021, 8:09 p.m.
I've learned so much from this solution

pokryshkin on March 21, 2021, 1:15 p.m.
I've copied that

Esmeron on April 6, 2021, 1 p.m.
I used a regex in a loop, but not nearly as efficient, gotta keep going. Amazing solution, simple and clear

BlindB on April 23, 2021, 11:03 a.m.
Good solution to demondtrate basic regexp methods.

spirit88 on May 13, 2021, 7:45 p.m.
Good and clear solution!

ChromeBrainer on May 19, 2021, 6:26 a.m.
Regex is useful in such cases.

2dfsdfl on June 8, 2021, 9:41 a.m.
return re.search 1234567890 1234567890 1234567890

2dfsdfl on June 16, 2021, 8:47 a.m.
wow I made some for loops and isalpha() I think I still have a long way to go… but I keep on going.

alterGNU on July 2, 2021, 9:24 a.m.
You make me love REGEX xD

alterGNU on July 22, 2021, 6:14 p.m.
<a href="https://py.checkio.org/mission/first-word/publications/alterGNU/python-3/re/">.</a>

2dfsdfl on July 15, 2021, 9:22 a.m.
good dddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddsdsd

2dfsdfl on July 21, 2021, 8:13 a.m.
goooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooood

jsg-inet on July 21, 2021, 6:37 p.m.
Compact and smart! Re has a lot of things to learn!

2dfsdfl on Aug. 2, 2021, 8:19 a.m.
goooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooood

mr_vads on Aug. 16, 2021, 2:19 p.m.
nice job!

Jason3254 on Aug. 19, 2021, 10 a.m.
Thanks for demonstrating the power of regular expression!

JoannaBu on Aug. 26, 2021, 7:20 p.m.
this is a really cool solution! so the group is begin with 1 instead of 0?

OGR on Sept. 27, 2021, 8 a.m.
I really need to dive in re module so powerful. What about efficiency?

HiKaGe_2f7a7d6ea64442c9ac4b033 on Nov. 25, 2021, 12:47 p.m.
I have learned a lot of things from this.

SpeakingCucumber on Nov. 28, 2021, 7:51 p.m.
So, here, with help of reg-ex, code will search for words (by pattern "([\w']+)") in string "text", and after it - will select first one. Amazing!

navicku.marius on Dec. 6, 2021, 8:56 p.m.
Beautiful! :)

jorgej on Dec. 12, 2021, 3:27 a.m.
Great, it works. But, wouldn't it be better to mark the string as raw (with an r)? just to be sure that while parsing the \ is not interpreted as escape character..

r_tchaik on Jan. 1, 2022, 11:46 a.m.
Very nice and educative. Well done!

H0r4c3 on Jan. 1, 2022, 3:44 p.m.
Nice! re is so powerful! And the use of group() makes it even more powerful.

ajay24 on April 11, 2022, 8:18 a.m.
Regular Expression are always good for such problems. Concise and Easily Readable. Easy to change according to requirements.

bykov.dmitry.nn on May 27, 2022, 6:52 a.m.
Thank you. Some solutions are very inventive. I have learned a lot of new things.

sevaa007.android on June 5, 2022, 12:14 a.m.
good

zongareight on Aug. 1, 2022, 5:49 p.m.
This is great. The solution is short and easy to read. Since \w also includes numbers and the "_" character, if there are numbers in the text, this expression may not work correctly. However, in this problem it is not critical, since the restrictions on the input data (a-z A-Z ) are explicitly set. It's work.

josip997 on Dec. 15, 2022, 9:39 a.m.
Nice going, but I doubt it's meant for clear category.

jv43 on Feb. 22, 2023, 4:23 a.m.
i like this one.

Adrian_Sanz_Wallace on March 14, 2023, 3:51 p.m.
Nice!! I've done something similar, but I like yours better.

TheRing on March 22, 2023, 3:02 p.m.
Great simple solution! I made a longer RE, nice to see that it can be done in an easier way.

toyosimasinn_15c0370466af400ba on May 17, 2023, 6:59 a.m.
jyu

toyosimasinn_15c0370466af400ba on May 17, 2023, 7:01 a.m.
Gqcuhgvauefhaui;fhl agivukj hcki,vujtsgfyucjtzergkduvkfyjbgnfhdss qgfuhfujguftufyfuhfgyfuyryf7dcgtudhyhfuihdufyughgyuhgbjkghujihbfyhgfycfggyucybbvjkyhvnnmuvh nnhvjv njujvhbhjbgchycgb hyfdgbfgyvhdkbef bn8jsgrw bmfbu8j9rhb fwnhcdujr3efsdhnhrjwjwyfdoysgt uawesdivct7grej

eegoldstraw on May 28, 2023, 6:11 p.m.
Great. Haven't seen this method before. Time for me to learn something new. Maybe some comments would help)

sinn on Oct. 29, 2023, 7:57 a.m.
nice good!

adamspj on Feb. 16, 2024, 8:33 p.m.
Ah, good catch to get that apostrophe in there. I'm only starting to get used to reading regular expressions, and at first I wasn't sure how to interpret that, but of course it's because apostrophes are a normal feature of a word. Heh.

mangeurdecowan on April 15, 2024, 8:49 p.m.
123456789012345678901234567890 re FTW!!

murnet on May 3, 2024, 11:36 a.m.
Сlear and simple code. In my code for this task I use a named group to add a little more clarity

TrexxaByte on July 19, 2024, 2:14 p.m.
I ask this question genuinely because I'm really not sure, but is the use of .isalpha() not as efficient or quicker than importing anything? Asking so that I know in the future... this solution is definitely shorter than mine in terms of lines of code, but if you can avoid importing a module, is it generally a quicker calculation/computation to execute?

jrchionis on Aug. 26, 2024, 9:13 p.m.
Reading these comments, it seems I'm not the only one that struggles with regular expressions ^__^ Thanks for serving up a bite sized morsel to chew on.

yegor.yefremov on Aug. 30, 2024, 6:30 a.m.
Clear and efficient. "re" module is a must have for many tasks.

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