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First solution in Clear category for Find Sequence by cinekk
def checkio(matrix):
check = False
for i in range(len(matrix)):
for j in range(len(matrix[i])):
if j < len(matrix[i])-3:
if matrix[i][j] == matrix[i][j+1] and matrix[i][j] == matrix[i][j+2] and matrix[i][j] == matrix[i][j+3]:
check = True
break
if i < len(matrix)-3:
if matrix[i][j] == matrix[i+1][j] and matrix[i][j] == matrix[i+2][j] and matrix[i][j] == matrix[i+3][j]:
check = True
break
if i < len(matrix)-3 and j < len(matrix[i])-3:
if matrix[i][j] == matrix[i+1][j+1] and matrix[i][j] == matrix[i+2][j+2] and matrix[i][j] == matrix[i+3][j+3]:
check = True
break
if i < len(matrix)-3 and j >= 3:
if matrix[i][j] == matrix[i+1][j-1] and matrix[i][j] == matrix[i+2][j-2] and matrix[i][j] == matrix[i+3][j-3]:
check = True
break
return check
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio([
[1, 2, 1, 1],
[1, 1, 4, 1],
[1, 3, 1, 6],
[1, 7, 2, 5]
]) == True, "Vertical"
assert checkio([
[7, 1, 4, 1],
[1, 2, 5, 2],
[3, 4, 1, 3],
[1, 1, 8, 1]
]) == False, "Nothing here"
assert checkio([
[2, 1, 1, 6, 1],
[1, 3, 2, 1, 1],
[4, 1, 1, 3, 1],
[5, 5, 5, 5, 5],
[1, 1, 3, 1, 1]
]) == True, "Long Horizontal"
assert checkio([
[7, 1, 1, 8, 1, 1],
[1, 1, 7, 3, 1, 5],
[2, 3, 1, 2, 5, 1],
[1, 1, 1, 5, 1, 4],
[4, 6, 5, 1, 3, 1],
[1, 1, 9, 1, 2, 1]
]) == True, "Diagonal"
Oct. 28, 2016
