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First solution in Clear category for Find Sequence by Lipen
def checkio(matrix):
#replace this for solution
n = len(matrix)
for i in range(n):
row = matrix[i]
for j in range(n):
if n-j>=4:
if matrix[i][j]==matrix[i][j+1]==matrix[i][j+2]==matrix[i][j+3]:
return True
if n-i>=4:
if matrix[i][j]==matrix[i+1][j]==matrix[i+2][j]==matrix[i+3][j]:
return True
if n-j>=4 and n-i>=4:
if matrix[i][j]==matrix[i+1][j+1]==matrix[i+2][j+2]==matrix[i+3][j+3]:
return True
if j>=3 and n-i>=4:
if matrix[i][j]==matrix[i+1][j-1]==matrix[i+2][j-2]==matrix[i+3][j-3]:
return True
return False
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio([
[1, 2, 1, 1],
[1, 1, 4, 1],
[1, 3, 1, 6],
[1, 7, 2, 5]
]) == True, "Vertical"
assert checkio([
[7, 1, 4, 1],
[1, 2, 5, 2],
[3, 4, 1, 3],
[1, 1, 8, 1]
]) == False, "Nothing here"
assert checkio([
[2, 1, 1, 6, 1],
[1, 3, 2, 1, 1],
[4, 1, 1, 3, 1],
[5, 5, 5, 5, 5],
[1, 1, 3, 1, 1]
]) == True, "Long Horizontal"
assert checkio([
[7, 1, 1, 8, 1, 1],
[1, 1, 7, 3, 1, 5],
[2, 3, 1, 2, 5, 1],
[1, 1, 1, 5, 1, 4],
[4, 6, 5, 1, 3, 1],
[1, 1, 9, 1, 2, 1]
]) == True, "Diagonal"
Sept. 10, 2014
