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Clear solution in Clear category for Feed Pigeons by slchangtw
def checkio(number):
n_pigeons, minute = 0, 0
while number > n_pigeons:
minute += 1
n_pigeons += minute
number -= n_pigeons
# If the number of feed is negetive,
# it means only (number + n_pigeons) pigeons have food.
return (number + n_pigeons) if number < 0 else n_pigeons
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(1) == 1, "1st example"
assert checkio(2) == 1, "2nd example"
assert checkio(5) == 3, "3rd example"
assert checkio(10) == 6, "4th example"
July 18, 2022
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